Programming Assembly Code Question
ANSWER
To transfer a value of 15 (presuming it is a 16-bit integer) to the GAMMA memory address, The following instruction sequence can be used with SIC (Simplified Instructional Computer) instructions:
Assuming that GAMMA is defined as a symbolic label that points to a memory address, your SIC program would need first to define GAMMA’s address. Assume for the moment that GAMMA is placed at hexadecimal memory address 2000. You may make the following declaration:
assemblage
Make a copy of the code GAMMA WORD 0 and define GAMMA at memory address 2000.
You can now relocate the number 15 to the GAMMA memory location. The set of SIC instructions to accomplish it is as follows:
assemblage
Take a copy of the LDA-GAMMA code; Insert the address of GAMMA into the STA-15 accumulator; Put the number 15 into the memory address that the accumulator has shown.
LDA GAMMA: Fill the accumulator with the address of GAMMA. This command loads the GAMMA label’s memory address into the accumulator.
STA 15: Insert the number 15 into the memory address that the accumulator has indicated. This instruction inserts the value 15 into the memory location GAMMA since the accumulator contains the address of GAMMA.
Following the execution of these two instructions, the value 15 will be present in the memory location GAMMA.
Note that the precise syntax and addressing mode details may change depending on the assembly language and SIC architecture you are using. Therefore, you need to modify the instructions to fit the needs of the system you are working with.
Question Description
I’m working on a programming writing question and need an explanation and answer to help me learn.
- Write a sequence of SIC instructions that move a value 15 of type word to the memory location GAMMA.
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